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Dancing x times on a y point board? Excel help?

Posted By: Ray Kershaw
Date: Thursday, 19 November 2015, at 3:55 p.m.

In Response To: Dancing x times on a y point board? Excel help? (sebalotek)

Let the probability of success on a single roll = p

In a large number of rolls, n, you will have np successes.

Average rolls = total rolls / successes = n / np = 1/p.

When p = 11/36, the probability of rolling the one number which enters from the bar, the average = 36/11 = 3.27.

Like most questions, it was answered over 30 years ago by Danny Kleinman. An alternative proof is given in Walter Trice's Backgammon Boot Camp.

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