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Probability of rolling at least 2 double 6s in 3 rolls

Posted By: leobueno
Date: Friday, 9 May 2014, at 8:25 p.m.

In Response To: Probability of rolling at least 2 double 6s in 3 rolls (AP)

Leo previously said: P = 1+35+35+35/1+35+35+1225+35+1225+1225+42876

As AP pointed out, the last term is off by one (should be 35*35*35 = 42875), thus

106/46656 = 0.00227 = 1/440.2

I should have caught the typo since the total number of outcomes is

36*36*36 = 46656.

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